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Is there a way to generate TeamViewer Passwords in Excel?

AhmedAlik
AhmedAlik Posts: 1
edited November 2021 in General Questions

I am attempting to make Excel generate a 6-character password string, exactly like TeamViewer (3 letters, 3 numbers). Is there a function I might be unaware of?

I have tried =CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122)))&CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122)))&CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122)))&CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122)))&CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122)))&CHOOSE(RANDBETWEEN(1,2),CHAR(RANDBETWEEN(0,9)),CHAR(RANDBETWEEN(97,122))), and here's an example of one of the results: ckjfs.

Please see above for the Formula.

The expected result is something like: aaa111, or 1aaa11. I don't want the Formula to allow something like 11aaaaaaaaaa, or 1234aa.

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Answers

  • rafiaSidiq12
    rafiaSidiq12 Posts: 1 Newbie

    @AhmedAlik Here is an option for you to consider:

    https://imgur.com/S97xQ2w

    Formula in A2:

    =RANDBETWEEN(1,6)
    

    Formula in B2:

    =CHAR(RANDBETWEEN(IF(OR(RANK.EQ(A2,$A$2:$A$7)+COUNTIF($A$2:A2,A2)-1={1,2,3}),48,97),IF(OR(RANK.EQ(A2,$A$2:$A$7)+COUNTIF($A$2:A2,A2)-1={1,2,3}),57,122)))
    

    Drag down.....

    Formula in D2:

    Excel 2016 with CONCAT:

    =CONCAT(C2:C7)
    

    Lower versions without CONCAT:

    =C2&C3&C4&C5&C6&C7
    


  • Minahil_Malik
    Minahil_Malik Posts: 1 Newbie

    @AhmedAlik I can Offer this rather long array formula:

    =ArrayFormula(TEXTJOIN("",TRUE,IF(MID(TEXT(DEC2BIN(INDEX({7,11,13,14,19,21,22,25,26,28,35,37,38,41,42,44,49,50,52,56},RANDBETWEEN(1,20))),"000000"),{1,2,3,4,5,6},1)="0",
    CHAR(CHOOSE({1,2,3,4,5,6},RANDBETWEEN(48,57),RANDBETWEEN(48,57),RANDBETWEEN(48,57),RANDBETWEEN(48,57),RANDBETWEEN(48,57),RANDBETWEEN(48,57))),
    CHAR(CHOOSE({1,2,3,4,5,6},RANDBETWEEN(97,122),RANDBETWEEN(97,122),RANDBETWEEN(97,122),RANDBETWEEN(97,122),RANDBETWEEN(97,122),RANDBETWEEN(97,122))))))
    

    I had to test it in Google Sheets because I only have an old version of Excel without the array concatenation features - it should work in later versions of Excel if you remove the ArrayFormula wrapper and enter it with Ctrl-Shift-Enter.

    The idea is that there are only 20 ways of selecting 3 items (letters) out of 6 (letters and numbers) so choose one of them in binary (e.g. 010101) and generate letters where there are 1's and numbers where there are 0's.